Two bulbs of 60 W each operate for 8 hours a day. Calculate the energy consumed by the bulbs in kWh, for one month of 30 days
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Answer:
Energy consumed by the bulbs in kWh, for one month of 30 days is 28.8 kWh.
Explanation:
Given:
Two bulbs of 60 W each operate for 8 hours a day.
To find:
Energy consumed by the bulbs in kWh, for one month of 30 days is 28.8 kWh.
Solution:
In the question it is given that, power of each bulb is 60 W. So, power of 2 bulbs will be 2 × 60
= 120 W
and time (t) is 8 hours.
Energy consumed in one day will be P × t
= 120 × 8
= 960 Wh.
Therefore, energy consumed in 30 days
= 960 Wh × 30
= 28800 Wh
So, energy consumed by the bulbs in kWh, for 30 days
= 28800/1000 kWh
= 28.8 kWh.
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