Physics, asked by aarohimishra1, 6 months ago

Two bulbs of 60 W each operate for 8 hours a day. Calculate the energy consumed by the bulbs in kWh, for one month of 30 days​

Answers

Answered by Anonymous
25

Answer:

Energy consumed by the bulbs in kWh, for one month of 30 days is 28.8 kWh.

Explanation:

Given:

Two bulbs of 60 W each operate for 8 hours a day.

To find:

Energy consumed by the bulbs in kWh, for one month of 30 days is 28.8 kWh.

Solution:

In the question it is given that, power of each bulb is 60 W. So, power of 2 bulbs will be 2 × 60

= 120 W

and time (t) is 8 hours.

Energy consumed in one day will be P × t

= 120 × 8

= 960 Wh.

Therefore, energy consumed in 30 days

= 960 Wh × 30

= 28800 Wh

So, energy consumed by the bulbs in kWh, for 30 days

= 28800/1000 kWh

= 28.8 kWh.

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