Two bullets P and Q,masses 10 g and 20 g,are moving with the same distance towards the target with velocities 20 m/s and 10 m/s.Which one of the bullets will pierce a greater distance from the target.
The answer is P. Plzz tell me the solution with formula and how
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mass of P = 10 g = 10 / 1000 = 0.01 kg
velocity of P = 20 m/s
initial of P = 0 m / s
mass of Q = 20 g = 20 / 1000 = 0.02 kg
velocity of Q = 10 m/s
initial of Q = 0 m / s
acceleration of P and Q = 10 m / s
distance of P ,
2as = v² - u²
2 * 10 * s = 20²- 0²
20 * s = 400
s = 400 / 20
s = 20 m
distance of Q ,
2as = v² - u²
2 * 10 * s = 10² - 0²
20 * s = 100
s = 100 / 20
s = 5 m
therefore the answer is P .
i hope that my answer will help u ..............................^_^
velocity of P = 20 m/s
initial of P = 0 m / s
mass of Q = 20 g = 20 / 1000 = 0.02 kg
velocity of Q = 10 m/s
initial of Q = 0 m / s
acceleration of P and Q = 10 m / s
distance of P ,
2as = v² - u²
2 * 10 * s = 20²- 0²
20 * s = 400
s = 400 / 20
s = 20 m
distance of Q ,
2as = v² - u²
2 * 10 * s = 10² - 0²
20 * s = 100
s = 100 / 20
s = 5 m
therefore the answer is P .
i hope that my answer will help u ..............................^_^
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