Two buses start from a bus stand with velocities 10km/hr and 30km/hr along two tracks inclined at an angle 60°.find the distance between them after 12 minutes?
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62
v₁ = 10 km/h = 50/18 m/s
v₂ = 30 km/h = 150/18 m/s
t = 12 min = 720 s
distance travelled S₁ = 50/18 x 720 = 2000m = 2 km
s₂ = 150/18 x 720 = 6000m = 6km
so this tells us that right angled triangle will be made
let x be the distance between the two buses
6² = 2² + x²
36 = 4 + x²
x² = 32
x = 5.65 km is the distance
v₂ = 30 km/h = 150/18 m/s
t = 12 min = 720 s
distance travelled S₁ = 50/18 x 720 = 2000m = 2 km
s₂ = 150/18 x 720 = 6000m = 6km
so this tells us that right angled triangle will be made
let x be the distance between the two buses
6² = 2² + x²
36 = 4 + x²
x² = 32
x = 5.65 km is the distance
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16
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