Question

Two candidates contested an election. One of them secured 62% votes and won the election by a margin of 4320 votes. How many votes were polled in all?

Answer 1

Answer:

assuming there are only two candidates in the election(A &B)

X = total no. Of votes

the candidate in talk here is A he gets 58% of votes polled

so A votes=58x/100

similarly rest of the candidates lets give the name B

so B=42x/100

now the margin of victory is 18336

hence A-B=18336

that is 58x/100–42x/100=18336

so x=114600

vote of A=66468

B=48132

margin A-B=18336

final answer total votes would be 114600

Answer 2

Answer:

Let total votes be x.

Let total votes won by 1st candidate be x-4320.

Percentage of total votes 1st Candidate won = 62%.

Now,

62/100 × x = x-4320

62x = 100x - 432000

38x = 432000

x = 11368 (approx.)

Hence, total votes polled were 11368.

I hope this helps.