Question

Two capacitors each of 2uf are connected in parallel with a 100v battery then energy stored is

Answer 1

Answer:

net capacity will be 4 uf energy stored is cv.v /2 only

Answer 2

Explanation:

since capacitor are connected in series so total capacitance = 2uf+2uf= 4×10^-6

now total energy storred is

(cv^2)/2 = (4×10^-6×10^4)/2= 4×10^-2J= 0.04

hope it will help you