Question

Two capacitors having 6 microfarad and 4 microfarad are connected in series across 120V supply.
a) Find the equivalent capacitance.
b) Find the charge on each capacitor
c)How much work is done by the battery in charging the arrangement.​

Answer 1

ooh dear here is your answer ❤️❤️❤️❤️

Capacitance of the capacitor = \frac{14}{15}

15

14

microfarad

Given:

Two capacitors of capacitance 4 microfarad and 6 microfarad are connected in parallel

This combination is then connected in series to third capacitor.

The equivalent capacitance of the arrangement is \frac{10}{3}

3

10

microfarad

To find:

Capacitance of the capacitor.

Formula used:

For parallel connection,

\frac{1}{Equavalant \ capacitance}

Equavalant capacitance

1

= \frac{1}{C_1}

C

1

1

+ \frac{1}{C_2}

C

2

1

For series connection,

Equavalant capacitance = C_1 + C_2C

1

+C

2

Explanation:

For parallel connection.

\frac{1}{Equavalant \ capacitance}

Equavalant capacitance

1

= \frac{1}{C_1}

C

1

1

+ \frac{1}{C_2}

C

2

1

\frac{1}{Equavalant \ capacitance}

Equavalant capacitance

1

= \frac{1}{4}

4

1

+ \frac{1}{6}

6

1

Equavalant capacitance = \frac{24}{10}

10

24

= \frac{12}{5}

5

12

microfaranide.

This capacitor is connected with another capacitor with capacitance = C_3C

3

And Equavalant capacitance is \frac{10}{3}

3

10

microfarad

So \frac{12}{5}

5

12

+ C_3C

3

= \frac{10}{3}

3

10

C_3C

3

= \frac{10}{3}

3

10

- \frac{12}{5}

5

12

C_3C

3

= \frac{50-36}{15}

15

50−36

C_3C

3

= \frac{14}{15}

15

14

Capacitance of the capacitor = \frac{14}{15}

15

14

microfarad

To learn more...

1)A 500-ohm, 2-watt resistor and a 1500-ohm, 1-watt resistor are connected in parallel. what is the maximum voltage that can be applied across the parallel circuit without exceeding wattage ratings?

https://brainly.in/question/5652656

2)2 resistor of resistance 10 ohm and 20 ohm are connected in parallel battery supplies 6 ampere of current to combination calculate the current in each resistor