Question

Two capacitors, of capacitance 3 micro farad and 6 micro farad are charged to potentials of 2V and 5V respectively. These two charged capacitors are connected in parallel . Find the charge across each of the two capacitors now.

Answer 1

Hope this is ur required answer.

Answer 2

Answer:

The charge on the two capacitors will be $12 \mu \mathrm{C}$ and $24 \mu \mathrm{C}.$

Explanation:

There are two given capacitance's of the value 3 micro farad and 6 micro farad and the two given potentials are 2 volt and 5 volt.

So charge on each will be $\mathrm{q}_{1}=3 \times 2=6 \mu \mathrm{C}$ and $\mathrm{q}_{2}=6 \times 5=30 \mu \mathrm{C}$

Total charge will be the sum of the two that is $30+6=36 \mu \mathrm{C}$

And total capacitance $=c_{1}+c_{2}=3+6=9 \mu F$

When connected in parallel the charge distribution over the capacitance's will be as follows:

 $\mathrm{Q}_{1}=\mathrm{c}_{1} \mathrm{xV}=12 \mu \mathrm{C}$ and

$Q_{2}=c_{1} \times V=24 \mu C$.