Two capacitors of capacitance 6mf and 12mf are connected in series with the battery. the voltage across the 6mf capacitor is 2 volt .compute the total battery voltage.
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Q=C1V1
Q=12
Q=C2V2
12=12V2
V2=1
V=V1+V2=3V
Q=12
Q=C2V2
12=12V2
V2=1
V=V1+V2=3V
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