two capacitors of capacitance 6uf and 12uf are connected in series with battery. the voltage across the 6uf capacitor is 2 V. compute the total battery voltage.
Ans=3V
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Answered by
118
charge on 6 uf capacitor will be equal to product of capacitance and potential difference.
= 6uf×2v
=12 u coulombs
there fore charge on 12uf capacitor will be equal 12 u coulombs. And potential difference across it will be
= capacitance = charge ÷ potential difference
therefore,
v = q÷c
v= 12 u c ÷ 12 uf
v = 1 volt
therefore total potential difference is
= 2v + 1v
= 3v
when my answer is right then make me brainliest
= 6uf×2v
=12 u coulombs
there fore charge on 12uf capacitor will be equal 12 u coulombs. And potential difference across it will be
= capacitance = charge ÷ potential difference
therefore,
v = q÷c
v= 12 u c ÷ 12 uf
v = 1 volt
therefore total potential difference is
= 2v + 1v
= 3v
when my answer is right then make me brainliest
Answered by
1
Answer:
3V
Explanation:
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