Question

two capacitors of capacitance 6uf and 12uf are connected in series with battery. the voltage across the 6uf capacitor is 2 V. compute the total battery voltage.
Ans=3V

Pls don't give any link

Answer 1

charge on 6 uf capacitor will be equal to product of capacitance and potential difference.
= 6uf×2v
=12 u coulombs

there fore charge on 12uf capacitor will be equal 12 u coulombs. And potential difference across it will be
= capacitance = charge ÷ potential difference
therefore,
v = q÷c
v= 12 u c ÷ 12 uf
v = 1 volt
therefore total potential difference is
= 2v + 1v
= 3v

when my answer is right then make me brainliest

Answer 2

Answer:

3V

Explanation:

Hope it helps u!!!!

Thanku..