Question

Two capacitors of capacitance C are connected in series. If one of them is filled with dielectric substance k, what is the effective capacitance?(a) $\frac{kC}{(1+k)}$(b) C(k + 1)(c) $\frac{2kC}{1+k}$(d) None of these

Answer 1

the answer is none of these

Answer 2

Answer:

Explanation:

C= EoAK/d

where, Eo= 8.854x10-12

K is the dielectric constant of the material,

A is the overlapping surface area of the plates,

d is the distance between the plates, and

C is capacitance of capacitor

For two capacitors C1, C2 connected in series, the equivalent capacitance Ce is given by:

Ce = C1×C2/(C1+C2)

Before the dielectric is inserted:

Ce = C×C/2C = C/2

When the dielectric is added to one capacitor its capacitance value now becomes k*C

So now Ce = k×C×C / C(k+1)

= C(k/(k+1))