Question

A one microfarad capacitor of a TV is subjected to 4000 V potential difference. The energy stored in capacitor is(a) 8 J(b) 16 J(c) 4 × 10⁻³ J(d) 2 × 10⁻³ J

Answer 1

Answer: 8J

Explanation:As we know, Energy = 1/2 CV2(C×V square)

Energy = 1/2 × 1×10°-6 × (4000)°2

= 1/2 × 1×10°-6×16× 10°+6

=1/2×1×16

=8Joule