Question

Two metal pieces having a potential difference of 800 V are 0.02 m apart horizontally. A particle of mass 1.96 × 10⁻¹⁵ kg is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is(a) 8(b) 6(c) 0.1(d) 3

Answer 1

Answer:

D) 3

Explanation:

Potential difference = 800V (Given)

Mass of particle = 1.96 × 10⁻¹⁵ (Given)

For equilibrium of a particle,

weight of particle = electrostatic force

mg = Qe

mg = qV/d

q = mgd/V

Therefore,

Q = 1.96 × 10⁻¹⁵ ×0.02 / 800

Q = 4.802*10^-19

Charge on the particle -

= 4.802*10^-19 / 1.6*10^-19

= 3

Thus, If e is the elementary charge, then charge on the particle is 3