two capacitrors c1=2mue F and c2=4mueF are coonnected in series and a potential diference of 1200 volt is aplied across it. the potential differnce acros 2meu F will be
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the total capacitance C=2*4/2+4=8/6=4/3mueF=4/3*10^ -6 F
potential difference V=1200v
voltage across 2meuF be=1200*4/(4+2)=1200*4/6=800v
potential difference V=1200v
voltage across 2meuF be=1200*4/(4+2)=1200*4/6=800v
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