Physics, asked by ibandiamai25, 4 months ago

two capcitors c1 =3 mf c2=6mf of potentials v1=2v and v2=5v are joined in series

Answers

Answered by ajr111

1

Answer:

common potential is 4V

Explanation:

Common potential is C1V1 + C2V2/C1+C2

3(2)+6(5)/3+6 = 36/9 = 4V

Hope it helps

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