Question

Two cards are drawn from a pack of 52 cards. The probability that one of the cards drawn is an ace and the other is a spade but none of the cards drawn is an ace of spades is

Answer 1

Answer:

1:18 and 1:4and 0

Step-by-step explanation:

probability of getting a ace is =4:56

so = 1:18

2) probability of getting a spade is = 13:52

so = 1:4

Answer 2

Probability of getting an ace of spades is 0.525

Given:

Number of cards drawn from a pack = 52

To Find:

probability of getting at least a spade and an ace.

Step-by-step explanation:

We know that,

probability of getting at least one space and one ace = 1 - p(getting non-spade and non-ace).

Let A' be the event of getting at least a non-spade and a non-ace.

Let A be the event of getting at least a spade and an ace.

Now No of remaining cards (non-spade and non-ace ) = 52-13-3

                                                                                           = 36

where 13 are spades including one ace and 3 are aces of other suits)

The number of ways two card can be drawn = $\frac{36}{2}$

and total number of ways drawing two cards from 52 cards are =$\frac{52}{2}$

∴ p( getting non-space and non-ace) =$\frac{\frac{36}{2} }{\frac{52}{2} }$ = $\frac{630}{1326}$ = 0.475.

Now p(getting at least a spade and an ace) = 1 - 0.475

                                                                        = 0.525.

The give question is incomplete -

Complete Question is :

Two cards are drawn from a pack of 52 cards. What is the probability of getting at least a spade and an ace?