Two cars A and B are at town P. They want to travel to town Q. Car A starts 15 minutes earlier than car B and maintains a constant speed of 20 m/s whereas car B starts from rest and maintains a constant acceleration. Car A takes 30 minutes to reach the destination. If car B wants to reach the destination at the same time the acceleration required is
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1
Answer:
Distance traveled by car A=S
A
Distance traveled by car B=S
B
According to formula S=ut+
2
1
at
2
S
A
=0t+
2
1
×2t
2
S
B
=10t+
2
1
×0t
2
Car A will overtake car B when
S
A
=S
B
+100
Putting the value S
A
and S
B
+2=10t+100
+2−10t−100=0
After solving for t, we get
t=16.18sec possible
t=−6.10sec not possible
So option B is correct.
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