Two cars are moving wither the speed of 30 kmph. They are separated from each other by 5 km. Third car in opposite direction meets the two cars after 4 mins. Speed of third car is
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Speed of third car =x.
It meets two cars in 4 minutes = 4/60hr 1/15hr.
Third car is moving opposite the two cars.
5=115∗(30+x)5=115∗(30+x)
x=45x=45
It meets two cars in 4 minutes = 4/60hr 1/15hr.
Third car is moving opposite the two cars.
5=115∗(30+x)5=115∗(30+x)
x=45x=45
Anusam25:
Can u explain the the calculation part??? I am not clear wid it
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