two cars are traveling towards each other over a stretch of 575 km. car A starts at 10:00am and is going at a speed of 80kmph.car B starts at 11:00am and is traveling at 70kmph. when and where will they meet?
Answers
Answered by
0
Let the duration car A traveled when they meet be h hours.
Therefore duration car B traveled when they meet will be (h-1) hours.
Distance Car A would have traveled = Speed x times = 80 x h = 80h km
Distance Car B would have traveled = Speed x times = 70 x (h - 1) = 70(h-1) km
The total distance covered is 575km:
80h + 70(h - 1) = 575 km
80h + 70h - 70 = 575
150h = 645
h = 4.3 hours = 4 hours 18 mins
10.00am + 4 hours 18 mins = 2.18pm
Distance Car A traveled = 80 x h = 80 x 4.3 = 344km
Answer: They will meet at 2.18pm at 344 km from the point Car A started.
Similar questions