Two cars leave a city and head in the same direction. After 7 hours, the faster car is 42 miles ahead of the slower car. The slower car has traveled 371 miles. Fine the speed of the two cars.
Answers
Let F = the speed of the faster car
S = the speed of the slower car
After 4 hours,
The slower car traveled 168 miles. Its speed can be determined by dividing the distance traveled by the time
Speed = Distance/time
= 168/4
42 miles per hour.
The faster car traveled 40 miles further than the slower car. So, the faster car has travelled for 208 miles (168+40). Therefore, its speed can be determined as follows
Speed = Distance/time
= 208/4
52 miles per hour.
Hence, the speed of the faster car is 52 miles per hour while the slower car travelled at a speed of 42 miles per hour.
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