Two cars leave Delhi at the same time, travelling in opposite directions.If the average speed of one car is 5km/hr more than that of other and they are 425 km apart at the end of 5hrs,what is the average speed of each?
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Answer:
car 1 =40 km/hr
car 2=40+5=45km/hr
Step-by-step explanation:
let the speed of one car be X km/hr
and of other be X+5km/hr
total av speed =(X+X+5)km/hr=2x+5km/hr
total distance=speed×time
425=(2x+5)×5
425=10x+25
425-25=10x
400/10=X
therefore, X=40km/hr
X+5=40+5=45km/hr
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