Question

Two cars left points A and B simultaneously, travel ling towards each other. Nine hours after their meet ing, the car travelling from A arrived at B, and sixteen hours after their meeting, the car travelling from arrived at A. How many hours did it take the slowe car to cover the whole distance?​

Answer 1

answer:

Let t hrs. be the time taken by the car B to reach the crossing point

Hence, A will take (t+1) hrs. to reach the same point

Speed of car B=50 km/hr

Distance covered before the crossing =50 × t

Now using the strategy (4), we know that the total distance covered by the two cars is the total distance between their starting points.

i.e. 40(t+1)+50t=400

⇒ 40t+50t+40=400

⇒ 90t=360

⇒ t=4 hrs

Hence, the distance covered by car B=50 × 4=200 km.