Two cars moving in the same direction with a speed of 40 km/h and are separated by a distance of 4 km. A cyclist moving in the opposite direction meets these cars after an interval of 5 min. The speed of the cyclist is:
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Explanation:
his is a question related to relative motion, here is the answer :-
let the two cars moving in same direction be A and B and the third car be C.
let the velocity of C be 'u'.
so velocity of C with respect to B would be. u+30(as they are moving in opposite directions).
do the speed u+30 would be given by
5/(4÷60) = u+30
5×60/4= u+30
75 = u+30
hence u = 45 kmph
Hope this helps my friend.☺
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