Question

Two cars start from one point and move along two roads, at right angles to each other. Their speeds are 36 and 48 kmph, respectively. After 15 seconds the distance between them is?

Answer 1

I hope u may not face any problem in understanding this.. Gud luck

Answer 2

Answer:

After 15 seconds the distance between the two cars is 250 m.

Step-by-step explanation:

Speed of car 1 = 36 km/hr. = 36 ×5/18 m/s =10m/s

Distance covered in 15 seconds = Speed x Time  

  = 10 m/s x 15 s = 150 m

Speed of car 2 = 48 km/hr. = 48 ×5/18 m/s =40/3m/s

Distance covered in 15 seconds = Speed x Time  

  = 40/3 m/s x 15 s = 200 m

Since, the 2 cars have started form a point and is moving at right angle to each other,

Hence, the distance between them = Hypotenuse of a right angled triangle.

Using Pythagoras Theorem,  

Distance between them$\begin{array}{l}{=\sqrt{150^{2}+200^{2}} \mathrm{m}} \\ {=\sqrt{22500+40000} m=\sqrt{62500} m=250 m}\end{array}$

The distance between the two cars is 250 m .