Two cars start off to race with velocities 4m/s and 2 m/s and travel in straight line with uniform acceleration 1m/s2 and 2m/s2 respectively. If they reach the final point at same time, then the length of path is
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4t+1/2×1×t^2=2t+1/2×2×t^2 as they reach on same time t solving above eqn we get t=0 and t=4 then use x=ut+1/2at^2 we get x=24 m
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Refer https://brainly.in/question/16279650
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