Math, asked by connectionerror1604, 1 year ago

- Two cars travel from city A to city B at a speed of 42 and 60 km/hr respectively. If one car takes 2 hours lesser time than the other car for the journey, then the distance between City A and City B is:

Answers

Answered by Ranu1111
9
I hope this will help u
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Answered by wifilethbridge
7

Answer:

280 km

Step-by-step explanation:

Let x be the distance between the City A and City B

Car 1:

Distance =x

Speed of Car 1 = 42 km/hr

Time =\frac{Distance}{Speed}

Time =\frac{x}{42}

Car 2:

Distance =x

Speed of Car 1 = 60 km/hr

Time =\frac{Distance}{Speed}

Time =\frac{x}{60}

Now we are given that one car takes 2 hours lesser time than the other car for the journey

So, \frac{x}{42}-\frac{x}{60}=2

\frac{10x-7x}{420}=2

\frac{3x}{420}=2

3x=2 \times 420

x=\frac{2 \times 420}{3}

x=280

Hence The distance between the City A and City B is 280 km.

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