Question

Two cell phones are purchased for Rs. 8000. One of them is sold at a profit of forty percent and the other one is sold at a loss of forty percent. The selling price was same in both the cases however.

Can you find out the cost price of the cell phones?

Answer 1

Answer:

2,400 and 5,600

Step-by-step explanation:

Let one instrument costs Rs. x

Another will cost (8,000 - x)

As it told that there is profit of 40% in one instrument and 40% loss in another instrument in both their S. P.

So,

S. P. of first instrument which costs Rs. x in 40% profit :-

= x + x of 40%

= 140x/100

And also, S. P. of another one which costs

₹ (8000 - x) with 40% loss :-

= (8000 - x) - 40(8000 - x)/100

= 480000 - 60x/100

\begin{gathered}\implies \: \frac{140x}{ \cancel{100} } = \frac{480000 - 60x}{ \cancel{100}} \\ \implies \: 140x = 480000 - 60x \\ \implies \: 140x = { 480000 - 60x}{{}} \\ \implies \:140x + 60x = 480000 \\ \implies \:200 x = 480000 \\ \implies \: x = \cancel { \frac{480000}{200} } \\ \implies \: x = 2400\end{gathered}

⟹

100

140x

=

100

480000−60x

⟹140x=480000−60x

⟹140x=480000−60x

⟹140x+60x=480000

⟹200x=480000

⟹x=

200

480000

⟹x=2400

Ones C. P. is ₹2400

Then anothers C. P. will be (8000 - x)

= 8000 - 2400

= ₹5600 ans.

Step-by-step explanation:

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Answer 2

the selling price of both two cell phone is ₹5600/-