Question

Two cells of 3V each are connected in parallel.An external resistance of 0.5 ohm is connected in series to the junction of two parallel resistors of 4ohm and 2ohm and then to common terminal of battery through each resistor as shown in fig. What is the current flowing through 4ohm resistor?​

Answer 1

we have,

potential difference v=3v

resistance= 1/4 + 1/2

1/r =1/4 + 2/4

1/r = 3/4

r=4/3

r=1.3

current= V/I=R

= 3/I=4

=3/4=I

=1.3=I

Answer 2

Answer:

0.55A

Explanation:

Rp = (4x2)/4+2 = 8/6 = 4/3= 1.33Ω

Total resistance of the circuit, R = 0.5+1.33 = 1.83Ω

Current in the circuit, I = V/R = 3/1.83 = 1.64A

Potential difference across 0.5Ω resistor, V1= 1.64 X 0.5 = 0.82V

Potential difference across 4Ω resistor, V2 = V-V1 = 3-0.82 = 2.18V

Thus, current flowing through 4Ω resistor,

I1= 2.18/4 = 0.55A

Hope this helps.