Two cells of EMF 1.5V & 2.0V & internal resistance of 1& 2 respectively are connected in parallel to an internal resistance of 5 Calculate the current in cach of the three branches of the network ?
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For the circuit diagram refer to the attachment.
According to Kirchhoff's Voltage Law , the sum of all voltages around a closed loop in any circuit must be equal to zero , hence here ; The net electromotive force around a closed circuit loop is equal to the sum of potential drops around the loop .
Let be the current through 1.5V cell ( Internal resistance = 1Ω) , and
be the current through 2V cell ( Internal resistance= 2Ω) .Then
will be the current through 5Ω resistor.
• Finding I1 :-
• Hence ,
Attachments:
![](https://hi-static.z-dn.net/files/dcc/fcfc72a70028ccda7b8558f9a4a491cb.jpg)
![](https://hi-static.z-dn.net/files/dcc/74bc22ca8267bc2dca41044e3d30e7f6.jpg)
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