Question

Two cells of emf 3v and 4v and internal resistance 1ohm and 2ohm respectivly are connected in parallel so as to send current in same direction through a external resistance of 5 ohm find current b/w each branch.<br />1.draw circuit diagram<br />2. using kirchhoffs laws calculate the current through each branch<br />3.pd across the 5ohm resistor​

Answer 1

Answer:

Explanation:

The question should be solved using Kirchoff's voltage Law.

So, we would have the following circuit diagram

and by using Kirchoff's Laws we get

in loop CDEBC,

2I2 + 50(I1 + I2) = 2 .................(1)

so,

50I1 + 52I2 = 2 ......................(2)

and

in loop CDFAC,

1I1 + 50(I1 + I2) = 1.5 .................(3)

so,

51I1 + 50I2 = 1.5 ......................(4)

now,

by solving for I1 and I2 we get

I1 = -0.144 amps

I2 = 0.177 amps

so,

the potential difference across the 50 ohm resistor will be

VCD = (I1 + I2) x 50 = (-0.144 + 0.177) x 50

thus, we have

VCD = 1.65 volts

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Answer 2

Answer:

vcd=1.65 volts is the answer. hope it helps you. Thanks.