Question

two cells of emf's E1and E2 are connected in series in a circuit. Let r1 and r2 be the internal resistance of the cells .the current through the circuit is
a) I = E1+E2/r1+r2
b) I = E1-E2/r1+r2
c). I = E1+E2/r1-r2
d). I = E1-E2/r1-r2
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Answer 1

Answer:

Option A

Explanation:

I=E1+E2/r1+r2