Two changes of +5uc and -2uc are placed at point (5cm ,0,0) and 2(23cm,0,0) in a region of space where there is no other external electric field.calculate potential energy of the charge system.
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Explanation:
Correct option is
B
−6×10
−4
J
Here the x-component of electric field is given only, i.e E
x
=250V/m
Thus, E
x
=−
dx
dV
or V=−∫
0
0.2
E
x
dx (as x varies from x=0 to x=20cm=0.2m)
or V=−250(0.2)=−50V
The change in potential energy =qV=12×10
−6
×(−50)=−6×10
−4
J
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