Physics, asked by shyamkumar3848, 1 year ago

Two charge q and -3q are placed fixed on X-axis seperated by distance d. where should a third charge 2q be placed such that it will not experience any force?

Answers

Answered by varghesemc100
0

KQ 2Q/x^{2} = K(3Q)(2Q)/(d+x) {2}  \\\\1/x^{2} =3/(d+x)^{2} \\\\(d+x)^{2} = 3x^{2}  \\\\x= d/\sqrt{3} -1

Attachments:

ksv369: wrong answer the answer is d/2 root 3 ➕ 1
lalit6395: guys the answer is (√3-1)d/2
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