Question

Two charges - 10 c and + 10 c are placed 10 cm apart . Potential at the centre of the line joining the two charges is

Answer 1

zero

as potential=KQ/r where the value of Q is to be put with sign and here net charge is zeo so potential will also be zero

Answer 2

Answer:

The electric potential at the center of the two charges is 0

Explanation:

• As we know that the electric potential due to any point charge q at a distance r is given by the formula
  $V = \frac{Kq}{r}$
• In the Question it is given to us that the charges are +10c and -10c and are seperated by 10cm.
• Now we have to find out the electric potential at the center of two charges so r = 5cm
• Now the electric potential is
  $V = \frac{K*10}{5} + \frac{K*-10}{5}\\V = 0$
• Hence the electric potential at the center of the two charges is 0
  #SPJ3