Question

Two charges +16 micro c and -6micro c are placed 8 cm apart in air determine the position of the point at which the resultant electric field is zero

Answer 1

Given :

q₁ = +16μC

q₂ = -6μC

To find :

The point at where resultant electric field is zero

Solution :

• Let P be the point where resultant electric field is zero and it is at a distance of x from 6μC away from the charges

• Electric field E = kq/r²

• By substituting the values

        6/x² = 16/(8-x)²

        x = 24 cm

The point should be 24 cm away from the 6μC charge

Answer 2

Answer:

Explanation:

Let P be the point where resultant electric field is zero and it is at a distance of x from 6μC away from the charges

Electric field E = kq/r²

By substituting the values

        6/x² = 16/(8-x)²

        x = 24 cm

The point should be 24 cm away from the 6μC charge