Question

Two charges 2uc and 4uc are separated by 3cm in a medium of dielectric constant 8 find the force between them

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Force=10\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Two \: charges = 2 \: \mu c\:and\:4\:\mu c \\ \\ \tt:\implies Dielectric\:constant(k_{o})=8 \\\\\tt: \implies Distance \: between \: them(r) = 0.03 \: m \\ \\ \red{\underline \bold{To \: Find : }} \\ \tt: \implies Force\:between\:two\:charges(F_{1}) = ?$

• According to given question :

$\tt \circ \: q_{1} = 2 \: \mu c \\ \\ \tt \circ \: q_{2} = 4 \: \mu c \\ \\ \tt \circ \: k = 9 \times {10}^{9} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies F= \frac{k q_{1}q_{2}}{{r}^{2} } \\ \\ \tt: \implies F= \frac{9 \times {10}^{9} \times 2 \times 4\times 10^{-6}\times 10^{-6}}{(0.03)^{2} } \\ \\ \tt: \implies F= \frac{72 \times {10}^{9-12} }{0.0009} \\ \\ \tt: \implies F = \frac{72 \times {10}^{-3+4} }{9} \\ \\ \tt: \implies F =8 \times 10^{1} \\ \\ \green{\tt: \implies F = 80 \: N} \\ \\ \bold{Force \: due \: to \: dielectric \: medium : } \\ \tt: \implies {F_{1}} = \dfrac{F}{k_{o}} \\ \\ \tt: \implies F_{1} =\dfrac{80}{8} \\ \\ \green{\tt: \implies F_{1} = 10 \: N}$

Answer 2

Answer:

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