Two charges 5 C ; -4 C are kept 5 m apart at point A ; B respectively. How much work is done to move the charge at A through a distance of 5 m further away from point B along the line BA.
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Answer: potential diff= Kqq/R
Charge= -4 +5 (just add)
Explanation:
Work =charge*potential difference
=(5-4C)* 9(10*9) (-20)/5
=-36(10*9)J
Hope this helps
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