Question

Two charges 5c and 15c are separated by 10cm. What is the force between them

Answer 1

0.75 N

i hope will be right answer

Answer 2

The force between charges is $6.75\times10^1^3N$.

Explanation:

The electrostatic force between two charges is given as

$F=\frac{1}{4\pi\epsilon_0} \frac{Qq}{r^2}$

Here, Q and q are two charges and r is the separation between them.

Given Q = 5 C, q = 15 C and r = 10 cm = 0.1 m and take  $\frac{1}{4\pi\epsilon_0} =9\times10^9 Nm^2/C^2$ .

Substitute the given values, we get

$F=9\times10^9Nm^2/C^2(\frac{5C\times15C}{(0.1m)^2})$

$F=9\times10^9Nm^2/C^2\times7500C^2/m^2$

$F=6.75\times10^1^3N$

Thus, the force between charges is $6.75\times10^1^3N$.

#Learn More: electric force.

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