Two charges are at distance d apart in air. Coulomb force between them is F. If a dielectric material of dielectric constant K is placed between them, the coulomb force now becomes
Answers
Answered by
1
The coulomb force will now become
F= 1/4πfE° q1 q2 /d^2
Answered by
8
Two charges are at distance d apart in air. Coulomb force between them is F. If a dielectric material of dielectric constant K is placed between them, the coulomb force now becomes F/K.
- Given,
- d is the distance between 2 charges.
- F is the Coulomb force between the 2 charges.
- K is the dielectric constant of a dielectric material placed between 2 charges.
- Now, let,
- F' be the new Coulomb force.
- as, we know that,
- Force ∝ 1/K
- we have, the new Coulomb force
- F' = F/K
Similar questions