Question

Two charges are at distance d apart in air. Coulomb force between them is F. If a dielectric material of dielectric constant K is placed between them, the coulomb force now becomes

Answer 1

The coulomb force will now become

F= 1/4πfE° q1 q2 /d^2

Answer 2

Two charges are at distance d apart in air. Coulomb force between them is F. If a dielectric material of dielectric constant K is placed between them, the coulomb force now becomes F/K.

• Given,
• d is the distance between 2 charges.
• F is the Coulomb force between the 2 charges.
• K is the dielectric constant of a dielectric material placed between 2 charges.
• Now, let,
• F' be the new Coulomb force.
• as, we know that,
• Force ∝ 1/K

• we have, the new Coulomb force

• F' = F/K