Question

Two charges, each of 0.1 uC, but opposite in sign, are
1 mm apart. What is the electric field at a point on
the line joining them at a distance of 0.1 m from the
mid-point ?​

Answer 1

Answer:

E

1

=E

2

=

r

2

kq

r

2

=(5)

2

+(

2

1

)

2

=25+

4

1

=

4

100+1

=

4

101

cm

2

E

1

=E

2

=

4

101

×10

−4

k×2×10

−6

=

101×10

−4

9×10

9

×2×4×10

−6

=

101

72

×10

7

v/m

cosθ=

hypotenuse

base

=

(5)

2

+(

2

1

)

2

2

1

=

25+

4

1

2

1

=

2

101

2

1

=

101

1

So

E

→

=2E

1

cosθ

=2×

101

72

×10

7

×

101

1

=

(101)

2

3

144×10

−7