Two charges, each of 0.1 uC, but opposite in sign, are
1 mm apart. What is the electric field at a point on
the line joining them at a distance of 0.1 m from the
mid-point ?
Answers
Answered by
4
Answer:
E
1
=E
2
=
r
2
kq
r
2
=(5)
2
+(
2
1
)
2
=25+
4
1
=
4
100+1
=
4
101
cm
2
E
1
=E
2
=
4
101
×10
−4
k×2×10
−6
=
101×10
−4
9×10
9
×2×4×10
−6
=
101
72
×10
7
v/m
cosθ=
hypotenuse
base
=
(5)
2
+(
2
1
)
2
2
1
=
25+
4
1
2
1
=
2
101
2
1
=
101
1
So
E
→
=2E
1
cosθ
=2×
101
72
×10
7
×
101
1
=
(101)
2
3
144×10
−7
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