two charges each of 1u but opposite in sign are 1cm apart. Calculate electric field at point distant 10cm from the mid point on axial line of the dipole.
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Here, q=1μC=10−6C,
2a=1cm=10−2m,r=10cm=10−1m
on the axial line of dipole,
E=2∣∣p→∣∣r4π∈0(r2−a2)2=2q×2a×r4π∈0(r2−a2)2
=9×109×2×10−6×10−2×10−1(10−2−0.25×10−4)2
1810−4(1−0.0025)2
E=18×1040.9975×0.9975=18×104N/C
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