Question

Two charges of+10uC and +40uC respectively are placed 12cm apart.Find the position of the point where electric field is zero

Answer 1

Answer:

0.005

Explanation:

let d be the distance of seperation between 2 charges.

let x be the point form charge +10muC to the point where electric field is =0

therefore,

x=√q1/(√q1+√q2)^2

x=√10/(√10+√40)^2

x=3.16/(3.16+20)^2

x=3.16/(23.16)^2

x=3.16/536.38

x=0.005