Question

Two opposite charges of magnitude 2×10^-7 are placed 15 cm apart .what is the magnitude of electric intensity at the point mid way between the charges

Answer 1

Answer:

3.2 x 10¹¹ N/C

Explanation:

Midpoint = 0.075 m

E = F/q = (1/4πë)(2 x 10^-7) ÷ 0.075²

= 9 x 10^9 x 2 x 10^-7 ÷ 5.625 x 10^-9

= 18 x 10¹¹ ÷ 5.625 = 3.2 x 10¹¹ N/C