Two opposite charges of magnitude 2×10^-7 are placed 15 cm apart .what is the magnitude of electric intensity at the point mid way between the charges
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Answer:
3.2 x 10¹¹ N/C
Explanation:
Midpoint = 0.075 m
E = F/q = (1/4πë)(2 x 10^-7) ÷ 0.075²
= 9 x 10^9 x 2 x 10^-7 ÷ 5.625 x 10^-9
= 18 x 10¹¹ ÷ 5.625 = 3.2 x 10¹¹ N/C
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