Question

two charges of 1C each are placed 1M apart in free space the force between them​

Answer 1

Electric force, $F=9\times 10^9\ N$

Explanation:

Given that,

Charges, $q_1=q_2=1\ C$

Distance, d = 1 m

Let F is the electric force between two charges. The force of attraction or repulsion between two charged particle is given by :

$F=k\dfrac{q_1q_2}{r^2}$

$F=9\times 10^9\times \dfrac{1^2}{1^2}$

$F=9\times 10^9\ N$

So, the electric force between two charges is $9\times 10^9\ N$. Hence, this is the required solution.

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Answer 2

The force between them is $9\times10^{9}\ N$

Explanation:

Given that,

Two charges = 1 C

Distance = 1 m

We need to calculate the force between them

Using formula of force

$F=\dfrac{kq_{1}q_{2}}{r^2}$

Where, $q_{1}$=first charge

$q_{2}$=second charge

r = distance

Put the value into the formula

$F=\dfrac{9\times10^{9}\times1\times1}{(1)^2}$

$F=9\times10^{9}\ N$

Hence, The force between them is $9\times10^{9}\ N$

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