Question

Two charges of 1C each are placed one meter apart in a free space The force will be
a)1N
b)9 x 10^9 N
c)9 x 10^-9 N
d)10 N​

Answer 1

Answer:

I think option (b ) is the right one ..

Answer 2

Answer: 9 × 10^9

Explanation: F= Kq1q2/r²

Therefore F = K×1×1/(1)²

F=K = 9 ×10^9 N. [ K=9×10^9]