Question

Two charges of +25nc and -25nc are placed 6 m apart

Answer 1

Given that,

q₁ = 25nC = 25×10⁻⁹ C

q₂ = -25nC = -25×10⁻⁹

r = 6m

We know that,

Force between the 2 charges = kq₁q₂/r²

F = kq₁q₂/r²

F = 9×10⁹×25×10⁻⁹×25×10⁻⁹/6²

F = 156.25×10⁻⁹

F = 1.5625×10⁷ N