Question

Two charges of magnitude -2q and +q are located at point(a,0) and(4a,0) respectively.What is the electric flux due to these charges through a sphere of radius 3a with its centre as the origin

Answer 1

Given that,

First charge (-2q) is placed at (a,0).

Second charge (+q) is placed at (4a,0).

Distance = 3a

Since, radius of sphere is 3a .

So, first charge will be outside the sphere.

We know that,

Gauss law :

The electric flux is equal to the charge divided by the $\epsilon_{0}$

Where, $\epsilon_{0}$ is electric constant

We need to calculate the electric flux due to charges

Using Gauss's law

$\phi=\dfrac{Q_{enclosed}}{\epsilon_{0}}$

Where, Q = charge

Put the value of charge

$\phi=\dfrac{-4q}{\epsilon_{0}}$

Hence, The electric flux due to charges is $\dfrac{-4q}{\epsilon_{0}}$