Question

two charges + q and - q located at point A( 0, 0, - 2 )and B( 0 0, 2) respectively how how much work will be done in moving test charge from point P (4, 0.0) and Q (- 5, 0, 0)

Answer 1

according to distance formula
the distance between the two charges is 2(root 2)

then find the force between the two charges

I.e F = kq1q2÷r^2

so F = -kq^2/8

now we know that work done = force × distance

distance of between p and q= -/41

W = (-kq^2 × -/41)÷8