Question

Two charges q1 and q2 separated by a dielectric of dielectric Constant 4 repel each other with a force of 10N. another charge q3 is placed between q1 and q2 such that the distance of q3 from q1 is 1/4 times the distance of q3 from q2. Now, the force of repulsion between q1 and q2 is?​

Answer 1

Answer:

F = 10N

Explanation:

Though a charge q3 is placed between the two charges, if the new charge does not alter the arrangement, then the force of repulsion will be the same between q1 and q2.

The net force acting on any one of the charge will be different. But from your question, the force between charge q1 and q2 will be the same as 10N

Thank you.