Question

Two children are at opposite ends of an aluminium rod. One
strikes the end of the rod with a stone. Find the ratio of times
taken by the sound wave in air and in aluminium to reach the
second child​

Answer 1

Explanation:

speed of sound in air = 346m/s

speed of sound in aluminium rod = 6420m/s

let the length of the rod be x

we know,

time = distance/speed

time taken in air = x/346

time taken in aluminium rod = x/6420

ratio =(x/346)/(x/6420)

= x/346 * 6420/x [reciprocal]

x would get cancelled

= 6420/346

after cancelling

= 18.55

Answer 2

AnswEr:

$\bf = Time \: taken = \frac{distance}{speed} \\ \\ \tt = \frac{TAL}{TAIR} = \frac{speed \: in \: air}{speed \: in \: aluminium} \\ \\ \tt = \cancel\frac{346}{6420} \\ \\ = \tt 0.054 \: \colon \: 1$

____________________________

$\huge\underline{\tt{Time\:taken:-}}$

Time taken to complete one vibration is called time period .

• Its SI units is Second.

• It is denoted by ( T ) .

$\implies$ The frequency of the wave is the reciprocal of the time period.

$\huge\nu$ = $\huge\tt\frac{1}{T}$ - is the formula to find the time period.