Two children having equal mass climb up a rope For reaching a height of 8 m A takes 20 s and B takes 15 sehat is work done by each who has done more work per second
Answers
Answered by
6
A has done more work in one second than B.
Explanation:
Correct statement:
Two children , A and B each weighing 50 kg start climbing up a rope separately . A takes 20 s while B takes 25 s to reach a height of 8m . what is the work done by each . who has done more work in 1s ?
Work done against the gravitational force by both children is same = mgh
Work done = 50 x 10 x 8 = 4000 J
Both have different power.
Work done per unit time is known as power.
Therefore the power of A and is calculated as.
Power of A = Work done / time = 4000 / 20 = 200 watt
Power of B = Work done / time = 4000 / 25 = 160 watt
A has done more work in one second than B.
Also learn about
What is work?what is power?
https://brainly.in/question/2245945
Similar questions