Question

Two children having equal mass climb up a rope For reaching a height of 8 m A takes 20 s and B takes 15 sehat is work done by each who has done more work per second

Answer 1

A has done more work in one second than B.

Explanation:

Correct statement:

Two children , A and B each weighing 50 kg start climbing up a rope separately . A takes 20 s while B takes 25 s to reach a height of 8m . what is the work done by each . who has done more work in 1s ?

Work done against the gravitational force  by both children is same = mgh

Work done = 50 x 10 x 8 = 4000 J

Both have different power.  

Work done per unit time is known as power.  

Therefore the power of A and  is calculated as.

Power of A = Work done / time = 4000 / 20 = 200 watt

Power of B = Work done / time = 4000 / 25 = 160 watt  

A has done more work in one second than B.

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